Base | Representation |
---|---|
bin | 1100011010001111011… |
… | …0010001011111011011 |
3 | 202101022102202120122202 |
4 | 3012203312101133123 |
5 | 11443114242424011 |
6 | 241535505240415 |
7 | 21255231513005 |
oct | 3064366213733 |
9 | 671272676582 |
10 | 213202311131 |
11 | 82467167a37 |
12 | 353a103310b |
13 | 171495a70b4 |
14 | a467671375 |
15 | 582c53a23b |
hex | 31a3d917db |
213202311131 has 4 divisors (see below), whose sum is σ = 213955676472. Its totient is φ = 212448945792.
The previous prime is 213202311107. The next prime is 213202311139. The reversal of 213202311131 is 131113202312.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213202311131 - 210 = 213202310107 is a prime.
It is a super-2 number, since 2×2132023111312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213202311139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376682246 + ... + 376682811.
It is an arithmetic number, because the mean of its divisors is an integer number (53488919118).
Almost surely, 2213202311131 is an apocalyptic number.
213202311131 is a deficient number, since it is larger than the sum of its proper divisors (753365341).
213202311131 is an equidigital number, since it uses as much as digits as its factorization.
213202311131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 753365340.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 213202311131 its reverse (131113202312), we get a palindrome (344315513443).
The spelling of 213202311131 in words is "two hundred thirteen billion, two hundred two million, three hundred eleven thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •