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21320312113 = 45194717927
BaseRepresentation
bin10011110110110010…
…100010010100110001
32001000211221001222101
4103312302202110301
5322130444441423
613443332140401
71353223443232
oct236662422461
961024831871
1021320312113
119050840061
124170167701
13201a0a50c9
1410637b3089
1584bb1e7ad
hex4f6ca2531

21320312113 has 4 divisors (see below), whose sum is σ = 21325034560. Its totient is φ = 21315589668.

The previous prime is 21320312081. The next prime is 21320312147. The reversal of 21320312113 is 31121302312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21320312113 - 25 = 21320312081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21320312213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2354445 + ... + 2363482.

It is an arithmetic number, because the mean of its divisors is an integer number (5331258640).

Almost surely, 221320312113 is an apocalyptic number.

It is an amenable number.

21320312113 is a deficient number, since it is larger than the sum of its proper divisors (4722447).

21320312113 is an equidigital number, since it uses as much as digits as its factorization.

21320312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4722446.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 21320312113 its reverse (31121302312), we get a palindrome (52441614425).

The spelling of 21320312113 in words is "twenty-one billion, three hundred twenty million, three hundred twelve thousand, one hundred thirteen".

Divisors: 1 4519 4717927 21320312113