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213211311405 = 3521757653311
BaseRepresentation
bin1100011010010001100…
…0100110110100101101
3202101100001200211201020
43012210120212310231
511443124043431110
6241540430204353
721255401146611
oct3064430466455
9671301624636
10213211311405
1182471254a84
12353a40536b9
131714b4088c1
14a468935341
15582d216d70
hex31a4626d2d

213211311405 has 16 divisors (see below), whose sum is σ = 341154299904. Its totient is φ = 113707298880.

The previous prime is 213211311403. The next prime is 213211311421. The reversal of 213211311405 is 504113112312.

It is not a de Polignac number, because 213211311405 - 21 = 213211311403 is a prime.

It is a super-2 number, since 2×2132113114052 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213211311403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 301 + ... + 653010.

It is an arithmetic number, because the mean of its divisors is an integer number (21322143744).

Almost surely, 2213211311405 is an apocalyptic number.

It is an amenable number.

213211311405 is a deficient number, since it is larger than the sum of its proper divisors (127942988499).

213211311405 is a wasteful number, since it uses less digits than its factorization.

213211311405 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 675076.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 213211311405 its reverse (504113112312), we get a palindrome (717324423717).

The spelling of 213211311405 in words is "two hundred thirteen billion, two hundred eleven million, three hundred eleven thousand, four hundred five".

Divisors: 1 3 5 15 21757 65271 108785 326355 653311 1959933 3266555 9799665 14214087427 42642262281 71070437135 213211311405