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2132141341247 is a prime number
BaseRepresentation
bin11111000001101101100…
…001101111101000111111
321112211102121002111112222
4133001231201233220333
5234413111140404442
64311254152315555
7310020310241561
oct37015541575077
97484377074488
102132141341247
11752266225325
122a52819a2bbb
131260a1c6cc18
14752a64c7331
153a6ddd228d2
hex1f06d86fa3f

2132141341247 has 2 divisors, whose sum is σ = 2132141341248. Its totient is φ = 2132141341246.

The previous prime is 2132141341223. The next prime is 2132141341273. The reversal of 2132141341247 is 7421431412312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2132141341247 - 216 = 2132141275711 is a prime.

It is a super-2 number, since 2×21321413412472 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2132141341207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066070670623 + 1066070670624.

It is an arithmetic number, because the mean of its divisors is an integer number (1066070670624).

Almost surely, 22132141341247 is an apocalyptic number.

2132141341247 is a deficient number, since it is larger than the sum of its proper divisors (1).

2132141341247 is an equidigital number, since it uses as much as digits as its factorization.

2132141341247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 32256, while the sum is 35.

Adding to 2132141341247 its reverse (7421431412312), we get a palindrome (9553572753559).

The spelling of 2132141341247 in words is "two trillion, one hundred thirty-two billion, one hundred forty-one million, three hundred forty-one thousand, two hundred forty-seven".