Base | Representation |
---|---|
bin | 1001101100100011100011… |
… | …11111011100001010010011 |
3 | 2210111101010220112012002001 |
4 | 10312101301333130022103 |
5 | 10243320210302110141 |
6 | 113203130142534431 |
7 | 4330321155403546 |
oct | 466216177341223 |
9 | 83441126465061 |
10 | 21322130113171 |
11 | 6880734644858 |
12 | 2484456297417 |
13 | bb888c1882a4 |
14 | 539dd497685d |
15 | 26e986a3ba31 |
hex | 136471fdc293 |
21322130113171 has 2 divisors, whose sum is σ = 21322130113172. Its totient is φ = 21322130113170.
The previous prime is 21322130113153. The next prime is 21322130113183. The reversal of 21322130113171 is 17131103122312.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21322130113171 is a prime.
It is a super-2 number, since 2×213221301131712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21322130114171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10661065056585 + 10661065056586.
It is an arithmetic number, because the mean of its divisors is an integer number (10661065056586).
Almost surely, 221322130113171 is an apocalyptic number.
21322130113171 is a deficient number, since it is larger than the sum of its proper divisors (1).
21322130113171 is an equidigital number, since it uses as much as digits as its factorization.
21322130113171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 21322130113171 its reverse (17131103122312), we get a palindrome (38453233235483).
The spelling of 21322130113171 in words is "twenty-one trillion, three hundred twenty-two billion, one hundred thirty million, one hundred thirteen thousand, one hundred seventy-one".
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