Base | Representation |
---|---|
bin | 11111000001110011000… |
… | …001010111000110110001 |
3 | 21112211200000112102210000 |
4 | 133001303001113012301 |
5 | 234413303234443231 |
6 | 4311311244100213 |
7 | 310022506561161 |
oct | 37016301270661 |
9 | 7484600472700 |
10 | 2132233515441 |
11 | 752303261147 |
12 | 2a52a8834669 |
13 | 1260b80a3673 |
14 | 752b483c5a1 |
15 | 3a6e6e7d6e6 |
hex | 1f0730571b1 |
2132233515441 has 40 divisors (see below), whose sum is σ = 3230134405344. Its totient is φ = 1401500257920.
The previous prime is 2132233515371. The next prime is 2132233515481. The reversal of 2132233515441 is 1445153322312.
2132233515441 is a `hidden beast` number, since 2 + 1 + 32 + 2 + 33 + 51 + 544 + 1 = 666.
It is a de Polignac number, because none of the positive numbers 2k-2132233515441 is a prime.
It is a super-3 number, since 3×21322335154413 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2132233515396 and 2132233515405.
It is not an unprimeable number, because it can be changed into a prime (2132233515481) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2978025 + ... + 3623961.
Almost surely, 22132233515441 is an apocalyptic number.
It is an amenable number.
2132233515441 is a deficient number, since it is larger than the sum of its proper divisors (1097900889903).
2132233515441 is an equidigital number, since it uses as much as digits as its factorization.
2132233515441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 646523 (or 646514 counting only the distinct ones).
The product of its digits is 86400, while the sum is 36.
Adding to 2132233515441 its reverse (1445153322312), we get a palindrome (3577386837753).
The spelling of 2132233515441 in words is "two trillion, one hundred thirty-two billion, two hundred thirty-three million, five hundred fifteen thousand, four hundred forty-one".
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