Base | Representation |
---|---|
bin | 11111000001110111000… |
… | …011100011111110010111 |
3 | 21112211211201220020022210 |
4 | 133001313003203332113 |
5 | 234413423101420203 |
6 | 4311322102524503 |
7 | 310024261106100 |
oct | 37016703437627 |
9 | 7484751806283 |
10 | 2132301201303 |
11 | 752338491579 |
12 | 2a5307436733 |
13 | 1260c9111a80 |
14 | 752bd81b3a7 |
15 | 3a6ecd9d803 |
hex | 1f0770e3f97 |
2132301201303 has 48 divisors (see below), whose sum is σ = 3561975999456. Its totient is φ = 1124626083840.
The previous prime is 2132301201301. The next prime is 2132301201311. The reversal of 2132301201303 is 3031021032312.
It is not a de Polignac number, because 2132301201303 - 21 = 2132301201301 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 2132301201303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132301201301) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23346975 + ... + 23438127.
It is an arithmetic number, because the mean of its divisors is an integer number (74207833322).
Almost surely, 22132301201303 is an apocalyptic number.
2132301201303 is a deficient number, since it is larger than the sum of its proper divisors (1429674798153).
2132301201303 is a wasteful number, since it uses less digits than its factorization.
2132301201303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103424 (or 103417 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 2132301201303 its reverse (3031021032312), we get a palindrome (5163322233615).
The spelling of 2132301201303 in words is "two trillion, one hundred thirty-two billion, three hundred one million, two hundred one thousand, three hundred three".
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