Base | Representation |
---|---|
bin | 11111000001110111000… |
… | …111000111101101100111 |
3 | 21112211211210122121220112 |
4 | 133001313013013231213 |
5 | 234413423321242434 |
6 | 4311322134523235 |
7 | 310024302042503 |
oct | 37016707075547 |
9 | 7484753577815 |
10 | 2132302134119 |
11 | 752338a693a3 |
12 | 2a530780651b |
13 | 1260c937a531 |
14 | 752bd9c1303 |
15 | 3a6eced4dce |
hex | 1f0771c7b67 |
2132302134119 has 2 divisors, whose sum is σ = 2132302134120. Its totient is φ = 2132302134118.
The previous prime is 2132302134091. The next prime is 2132302134139. The reversal of 2132302134119 is 9114312032312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2132302134119 - 216 = 2132302068583 is a prime.
It is a super-2 number, since 2×21323021341192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132302134139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066151067059 + 1066151067060.
It is an arithmetic number, because the mean of its divisors is an integer number (1066151067060).
Almost surely, 22132302134119 is an apocalyptic number.
2132302134119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132302134119 is an equidigital number, since it uses as much as digits as its factorization.
2132302134119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 2132302134119 in words is "two trillion, one hundred thirty-two billion, three hundred two million, one hundred thirty-four thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •