Base | Representation |
---|---|
bin | 11111000001110111000… |
… | …111000111110000111101 |
3 | 21112211211210122122012110 |
4 | 133001313013013300331 |
5 | 234413423321244313 |
6 | 4311322134524233 |
7 | 310024302043230 |
oct | 37016707076075 |
9 | 7484753578173 |
10 | 2132302134333 |
11 | 752338a69578 |
12 | 2a5307806679 |
13 | 1260c937a667 |
14 | 752bd9c1417 |
15 | 3a6eced4ec3 |
hex | 1f0771c7c3d |
2132302134333 has 16 divisors (see below), whose sum is σ = 3249765204480. Its totient is φ = 1218254773296.
The previous prime is 2132302134301. The next prime is 2132302134383. The reversal of 2132302134333 is 3334312032312.
It is not a de Polignac number, because 2132302134333 - 25 = 2132302134301 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 2132302134333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132302134383) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8354163 + ... + 8605616.
It is an arithmetic number, because the mean of its divisors is an integer number (203110325280).
Almost surely, 22132302134333 is an apocalyptic number.
It is an amenable number.
2132302134333 is a deficient number, since it is larger than the sum of its proper divisors (1117463070147).
2132302134333 is a wasteful number, since it uses less digits than its factorization.
2132302134333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16965776.
The product of its (nonzero) digits is 23328, while the sum is 30.
Adding to 2132302134333 its reverse (3334312032312), we get a palindrome (5466614166645).
The spelling of 2132302134333 in words is "two trillion, one hundred thirty-two billion, three hundred two million, one hundred thirty-four thousand, three hundred thirty-three".
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