213231131113133 has 4 divisors (see below), whose sum is σ = 243692721272160. Its totient is φ = 182769540954108.

The previous prime is 213231131113103. The next prime is 213231131113151. The reversal of 213231131113133 is 331311131132312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213231131113133 - 2¹² = 213231131109037 is a prime.

It is a super-2 number, since 2×213231131113133² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213231131113096 and 213231131113105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213231131113103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15230795079503 + ... + 15230795079516.

It is an arithmetic number, because the mean of its divisors is an integer number (60923180318040).

Almost surely, 2^{213231131113133} is an apocalyptic number.

It is an amenable number.

213231131113133 is a deficient number, since it is larger than the sum of its proper divisors (30461590159027).

213231131113133 is an equidigital number, since it uses as much as digits as its factorization.

213231131113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30461590159026.

The product of its digits is 2916, while the sum is 29.

Adding to 213231131113133 its reverse (331311131132312), we get a palindrome (544542262245445).

The spelling of 213231131113133 in words is "two hundred thirteen trillion, two hundred thirty-one billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred thirty-three".