Base | Representation |
---|---|
bin | 11111000001110111101… |
… | …101100011111101100111 |
3 | 21112211212111121121012120 |
4 | 133001313231203331213 |
5 | 234413433411230203 |
6 | 4311323134521023 |
7 | 310024453513161 |
oct | 37016755437547 |
9 | 7484774547176 |
10 | 2132312211303 |
11 | 75234372154a |
12 | 2a530b066173 |
13 | 1260cb498271 |
14 | 752c1085931 |
15 | 3a6edd25b53 |
hex | 1f077b63f67 |
2132312211303 has 4 divisors (see below), whose sum is σ = 2843082948408. Its totient is φ = 1421541474200.
The previous prime is 2132312211299. The next prime is 2132312211307. The reversal of 2132312211303 is 3031122132312.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (2132312211299) and next prime (2132312211307).
It is a cyclic number.
It is not a de Polignac number, because 2132312211303 - 22 = 2132312211299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132312211307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355385368548 + ... + 355385368553.
It is an arithmetic number, because the mean of its divisors is an integer number (710770737102).
Almost surely, 22132312211303 is an apocalyptic number.
2132312211303 is a deficient number, since it is larger than the sum of its proper divisors (710770737105).
2132312211303 is an equidigital number, since it uses as much as digits as its factorization.
2132312211303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 710770737104.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 2132312211303 its reverse (3031122132312), we get a palindrome (5163434343615).
The spelling of 2132312211303 in words is "two trillion, one hundred thirty-two billion, three hundred twelve million, two hundred eleven thousand, three hundred three".
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