Base | Representation |
---|---|
bin | 11111000001110111110… |
… | …001000010000101100011 |
3 | 21112211212120022211020121 |
4 | 133001313301002011203 |
5 | 234413434124333443 |
6 | 4311323210221111 |
7 | 310024464322543 |
oct | 37016761020543 |
9 | 7484776284217 |
10 | 2132313121123 |
11 | 752344193069 |
12 | 2a530b424797 |
13 | 1260cb726413 |
14 | 752c1241323 |
15 | 3a6ede554ed |
hex | 1f077c42163 |
2132313121123 has 2 divisors, whose sum is σ = 2132313121124. Its totient is φ = 2132313121122.
The previous prime is 2132313121093. The next prime is 2132313121153. The reversal of 2132313121123 is 3211213132312.
It is a balanced prime because it is at equal distance from previous prime (2132313121093) and next prime (2132313121153).
It is a cyclic number.
It is not a de Polignac number, because 2132313121123 - 25 = 2132313121091 is a prime.
It is a super-2 number, since 2×21323131211232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2132313121153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066156560561 + 1066156560562.
It is an arithmetic number, because the mean of its divisors is an integer number (1066156560562).
Almost surely, 22132313121123 is an apocalyptic number.
2132313121123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132313121123 is an equidigital number, since it uses as much as digits as its factorization.
2132313121123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296, while the sum is 25.
Adding to 2132313121123 its reverse (3211213132312), we get a palindrome (5343526253435).
The spelling of 2132313121123 in words is "two trillion, one hundred thirty-two billion, three hundred thirteen million, one hundred twenty-one thousand, one hundred twenty-three".
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