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213232311133 is a prime number
BaseRepresentation
bin1100011010010110100…
…0101101101101011101
3202101101112012201220221
43012211220231231131
511443144432424013
6241542500241341
721256044511402
oct3064550555535
9671345181827
10213232311133
1182482098426
12353ab0a0251
131715287c08a
14a46b6402a9
15582eeb408d
hex31a5a2db5d

213232311133 has 2 divisors, whose sum is σ = 213232311134. Its totient is φ = 213232311132.

The previous prime is 213232311113. The next prime is 213232311137. The reversal of 213232311133 is 331113232312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174739048324 + 38493262809 = 418018^2 + 196197^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213232311133 is a prime.

It is a super-2 number, since 2×2132323111332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213232311098 and 213232311107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213232311137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106616155566 + 106616155567.

It is an arithmetic number, because the mean of its divisors is an integer number (106616155567).

Almost surely, 2213232311133 is an apocalyptic number.

It is an amenable number.

213232311133 is a deficient number, since it is larger than the sum of its proper divisors (1).

213232311133 is an equidigital number, since it uses as much as digits as its factorization.

213232311133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1944, while the sum is 25.

Adding to 213232311133 its reverse (331113232312), we get a palindrome (544345543445).

The spelling of 213232311133 in words is "two hundred thirteen billion, two hundred thirty-two million, three hundred eleven thousand, one hundred thirty-three".