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21324113 is a prime number
BaseRepresentation
bin101000101011…
…0000101010001
31111010101011222
41101112011101
520424332423
62041014425
7346152266
oct121260521
944111158
1021324113
1111045138
127184415
134558025
142b9126d
151d133c8
hex1456151

21324113 has 2 divisors, whose sum is σ = 21324114. Its totient is φ = 21324112.

The previous prime is 21324109. The next prime is 21324119. The reversal of 21324113 is 31142312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19864849 + 1459264 = 4457^2 + 1208^2 .

It is a cyclic number.

It is not a de Polignac number, because 21324113 - 22 = 21324109 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 21324091 and 21324100.

It is not a weakly prime, because it can be changed into another prime (21324119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10662056 + 10662057.

It is an arithmetic number, because the mean of its divisors is an integer number (10662057).

Almost surely, 221324113 is an apocalyptic number.

It is an amenable number.

21324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21324113 is an equidigital number, since it uses as much as digits as its factorization.

21324113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 17.

The square root of 21324113 is about 4617.8039152827. The cubic root of 21324113 is about 277.3045475945.

Adding to 21324113 its reverse (31142312), we get a palindrome (52466425).

The spelling of 21324113 in words is "twenty-one million, three hundred twenty-four thousand, one hundred thirteen".