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21324113131 = 208110247051
BaseRepresentation
bin10011110111000001…
…000010010011101011
32001001010002011222211
4103313001002103223
5322132433110011
613443545425551
71353300654016
oct236701022353
961033064884
1021324113131
1190529a68a2
12417149b2b7
13201ab06229
1410640c237d
1584c120b21
hex4f70424eb

21324113131 has 4 divisors (see below), whose sum is σ = 21334362264. Its totient is φ = 21313864000.

The previous prime is 21324113123. The next prime is 21324113191. The reversal of 21324113131 is 13131142312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21324113131 - 23 = 21324113123 is a prime.

It is a super-2 number, since 2×213241131312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21324113191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5121445 + ... + 5125606.

It is an arithmetic number, because the mean of its divisors is an integer number (5333590566).

Almost surely, 221324113131 is an apocalyptic number.

21324113131 is a deficient number, since it is larger than the sum of its proper divisors (10249133).

21324113131 is a wasteful number, since it uses less digits than its factorization.

21324113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10249132.

The product of its digits is 432, while the sum is 22.

Adding to 21324113131 its reverse (13131142312), we get a palindrome (34455255443).

The spelling of 21324113131 in words is "twenty-one billion, three hundred twenty-four million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 2081 10247051 21324113131