Base | Representation |
---|---|
bin | 11111000001111111101… |
… | …101101001000101101111 |
3 | 21112212012212012122010022 |
4 | 133001333231221011233 |
5 | 234414222242400111 |
6 | 4311344332032355 |
7 | 310031003516552 |
oct | 37017755510557 |
9 | 7485185178108 |
10 | 2132446450031 |
11 | 752402479047 |
12 | 2a53480026bb |
13 | 126120239171 |
14 | 752d4c2a699 |
15 | 3a70a9e02db |
hex | 1f07fb6916f |
2132446450031 has 2 divisors, whose sum is σ = 2132446450032. Its totient is φ = 2132446450030.
The previous prime is 2132446449997. The next prime is 2132446450049. The reversal of 2132446450031 is 1300546442312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2132446450031 - 26 = 2132446449967 is a prime.
It is a super-2 number, since 2×21324464500312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2132446449973 and 2132446450000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132446456031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066223225015 + 1066223225016.
It is an arithmetic number, because the mean of its divisors is an integer number (1066223225016).
Almost surely, 22132446450031 is an apocalyptic number.
2132446450031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132446450031 is an equidigital number, since it uses as much as digits as its factorization.
2132446450031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
The spelling of 2132446450031 in words is "two trillion, one hundred thirty-two billion, four hundred forty-six million, four hundred fifty thousand, thirty-one".
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