Base | Representation |
---|---|
bin | 11111000010000100010… |
… | …110010110111000110011 |
3 | 21112212102021120101020222 |
4 | 133002010112112320303 |
5 | 234414402200412433 |
6 | 4311400151123255 |
7 | 310032636615056 |
oct | 37020426267063 |
9 | 7485367511228 |
10 | 2132524232243 |
11 | 752442374a69 |
12 | 2a536a07352b |
13 | 1261333a0c42 |
14 | 753012b6a9d |
15 | 3a712756b98 |
hex | 1f084596e33 |
2132524232243 has 2 divisors, whose sum is σ = 2132524232244. Its totient is φ = 2132524232242.
The previous prime is 2132524232239. The next prime is 2132524232269. The reversal of 2132524232243 is 3422324252312.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2132524232243 - 22 = 2132524232239 is a prime.
It is a super-2 number, since 2×21325242322432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2132524232233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066262116121 + 1066262116122.
It is an arithmetic number, because the mean of its divisors is an integer number (1066262116122).
Almost surely, 22132524232243 is an apocalyptic number.
2132524232243 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132524232243 is an equidigital number, since it uses as much as digits as its factorization.
2132524232243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 138240, while the sum is 35.
Adding to 2132524232243 its reverse (3422324252312), we get a palindrome (5554848484555).
The spelling of 2132524232243 in words is "two trillion, one hundred thirty-two billion, five hundred twenty-four million, two hundred thirty-two thousand, two hundred forty-three".
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