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213255040433 is a prime number
BaseRepresentation
bin1100011010011011111…
…1011010110110110001
3202101110002222111122212
43012212333122312301
511443221242243213
6241545031341505
721256441635521
oct3064677326661
9671402874585
10213255040433
1182493a02276
12353b6821895
13171574a9876
14a470679681
155831ea39a8
hex31a6fdadb1

213255040433 has 2 divisors, whose sum is σ = 213255040434. Its totient is φ = 213255040432.

The previous prime is 213255040403. The next prime is 213255040441. The reversal of 213255040433 is 334040552312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200643076624 + 12611963809 = 447932^2 + 112303^2 .

It is a cyclic number.

It is not a de Polignac number, because 213255040433 - 214 = 213255024049 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 213255040433.

It is not a weakly prime, because it can be changed into another prime (213255040403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106627520216 + 106627520217.

It is an arithmetic number, because the mean of its divisors is an integer number (106627520217).

Almost surely, 2213255040433 is an apocalyptic number.

It is an amenable number.

213255040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

213255040433 is an equidigital number, since it uses as much as digits as its factorization.

213255040433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 213255040433 its reverse (334040552312), we get a palindrome (547295592745).

The spelling of 213255040433 in words is "two hundred thirteen billion, two hundred fifty-five million, forty thousand, four hundred thirty-three".