Base | Representation |
---|---|
bin | 1001101100110010010010… |
… | …00111100100110011000001 |
3 | 2210112010112202200012210221 |
4 | 10312121021013210303001 |
5 | 10243432402241030213 |
6 | 113210514341223041 |
7 | 4331021064120235 |
oct | 466311107446301 |
9 | 83463482605727 |
10 | 21330034314433 |
11 | 6884020330199 |
12 | 2485aa1401a81 |
13 | bb954b8c8c60 |
14 | 53a5446245c5 |
15 | 26ec9a91238d |
hex | 1366491e4cc1 |
21330034314433 has 16 divisors (see below), whose sum is σ = 24322269202560. Its totient is φ = 18530888345856.
The previous prime is 21330034314427. The next prime is 21330034314461. The reversal of 21330034314433 is 33441343003312.
It is a cyclic number.
It is not a de Polignac number, because 21330034314433 - 241 = 19131011058881 is a prime.
It is a super-3 number, since 3×213300343144333 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21330034314493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25188316 + ... + 26021362.
It is an arithmetic number, because the mean of its divisors is an integer number (1520141825160).
Almost surely, 221330034314433 is an apocalyptic number.
It is an amenable number.
21330034314433 is a deficient number, since it is larger than the sum of its proper divisors (2992234888127).
21330034314433 is a wasteful number, since it uses less digits than its factorization.
21330034314433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 948936.
The product of its (nonzero) digits is 93312, while the sum is 34.
Adding to 21330034314433 its reverse (33441343003312), we get a palindrome (54771377317745).
The spelling of 21330034314433 in words is "twenty-one trillion, three hundred thirty billion, thirty-four million, three hundred fourteen thousand, four hundred thirty-three".
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