Base | Representation |
---|---|
bin | 1100011010100110111… |
… | …1001000001000111001 |
3 | 202101120022122122000222 |
4 | 3012221233020020321 |
5 | 11443320040213423 |
6 | 241553354505425 |
7 | 21260541305312 |
oct | 3065157101071 |
9 | 671508578028 |
10 | 213301101113 |
11 | 82507a02351 |
12 | 3540a135275 |
13 | 17163bb5bc9 |
14 | a476829609 |
15 | 58360513c8 |
hex | 31a9bc8239 |
213301101113 has 2 divisors, whose sum is σ = 213301101114. Its totient is φ = 213301101112.
The previous prime is 213301101109. The next prime is 213301101119. The reversal of 213301101113 is 311101103312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 167971284649 + 45329816464 = 409843^2 + 212908^2 .
It is a cyclic number.
It is not a de Polignac number, because 213301101113 - 22 = 213301101109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213301101091 and 213301101100.
It is not a weakly prime, because it can be changed into another prime (213301101119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106650550556 + 106650550557.
It is an arithmetic number, because the mean of its divisors is an integer number (106650550557).
Almost surely, 2213301101113 is an apocalyptic number.
It is an amenable number.
213301101113 is a deficient number, since it is larger than the sum of its proper divisors (1).
213301101113 is an equidigital number, since it uses as much as digits as its factorization.
213301101113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 213301101113 its reverse (311101103312), we get a palindrome (524402204425).
The spelling of 213301101113 in words is "two hundred thirteen billion, three hundred one million, one hundred one thousand, one hundred thirteen".
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