Base | Representation |
---|---|
bin | 110000011111111100010000… |
… | …111101000001010111111011 |
3 | 1000222020101210112020000201202 |
4 | 300133330100331001113323 |
5 | 210424211422241044430 |
6 | 2033353123405204415 |
7 | 62633335462434245 |
oct | 6037742075012773 |
9 | 1028211715200652 |
10 | 213301245253115 |
11 | 61a67606214448 |
12 | 1bb0b26356070b |
13 | 92032b4a52c56 |
14 | 3a95b9a2db095 |
15 | 199d6c53add45 |
hex | c1ff10f415fb |
213301245253115 has 4 divisors (see below), whose sum is σ = 255961494303744. Its totient is φ = 170640996202488.
The previous prime is 213301245253051. The next prime is 213301245253123. The reversal of 213301245253115 is 511352542103312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213301245253115 - 26 = 213301245253051 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21330124525307 + ... + 21330124525316.
It is an arithmetic number, because the mean of its divisors is an integer number (63990373575936).
Almost surely, 2213301245253115 is an apocalyptic number.
213301245253115 is a deficient number, since it is larger than the sum of its proper divisors (42660249050629).
213301245253115 is an equidigital number, since it uses as much as digits as its factorization.
213301245253115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42660249050628.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 213301245253115 its reverse (511352542103312), we get a palindrome (724653787356427).
The spelling of 213301245253115 in words is "two hundred thirteen trillion, three hundred one billion, two hundred forty-five million, two hundred fifty-three thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •