Base | Representation |
---|---|
bin | 1100011010101001000… |
… | …1001100110111000111 |
3 | 202101120221110102202121 |
4 | 3012222101030313013 |
5 | 11443324332031401 |
6 | 241554314150411 |
7 | 21261010236652 |
oct | 3065221146707 |
9 | 671527412677 |
10 | 213310033351 |
11 | 82511a53268 |
12 | 35411122407 |
13 | 171659c275c |
14 | a477ab2899 |
15 | 5836c17ca1 |
hex | 31aa44cdc7 |
213310033351 has 2 divisors, whose sum is σ = 213310033352. Its totient is φ = 213310033350.
The previous prime is 213310033331. The next prime is 213310033361. The reversal of 213310033351 is 153330013312.
213310033351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213310033351 - 25 = 213310033319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213310033331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106655016675 + 106655016676.
It is an arithmetic number, because the mean of its divisors is an integer number (106655016676).
Almost surely, 2213310033351 is an apocalyptic number.
213310033351 is a deficient number, since it is larger than the sum of its proper divisors (1).
213310033351 is an equidigital number, since it uses as much as digits as its factorization.
213310033351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2430, while the sum is 25.
Adding to 213310033351 its reverse (153330013312), we get a palindrome (366640046663).
The spelling of 213310033351 in words is "two hundred thirteen billion, three hundred ten million, thirty-three thousand, three hundred fifty-one".
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