Base | Representation |
---|---|
bin | 111111100100100… |
… | …1000111000100001 |
3 | 12111122210210222222 |
4 | 1333021020320201 |
5 | 13332033231423 |
6 | 551355440425 |
7 | 103601032412 |
oct | 17711107041 |
9 | 5448723888 |
10 | 2133102113 |
11 | 9a509820a |
12 | 4b6456115 |
13 | 27cc0aacc |
14 | 163425809 |
15 | c74053c8 |
hex | 7f248e21 |
2133102113 has 2 divisors, whose sum is σ = 2133102114. Its totient is φ = 2133102112.
The previous prime is 2133102109. The next prime is 2133102151. The reversal of 2133102113 is 3112013312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1951607329 + 181494784 = 44177^2 + 13472^2 .
It is a cyclic number.
It is not a de Polignac number, because 2133102113 - 22 = 2133102109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2133102091 and 2133102100.
It is not a weakly prime, because it can be changed into another prime (2133102173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066551056 + 1066551057.
It is an arithmetic number, because the mean of its divisors is an integer number (1066551057).
Almost surely, 22133102113 is an apocalyptic number.
It is an amenable number.
2133102113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2133102113 is an equidigital number, since it uses as much as digits as its factorization.
2133102113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
The square root of 2133102113 is about 46185.5184338121. The cubic root of 2133102113 is about 1287.2726692985.
Adding to 2133102113 its reverse (3112013312), we get a palindrome (5245115425).
The spelling of 2133102113 in words is "two billion, one hundred thirty-three million, one hundred two thousand, one hundred thirteen".
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