Base | Representation |
---|---|
bin | 110000100000000101010111… |
… | …001011001010011110010001 |
3 | 1000222021100000021112020011012 |
4 | 300200011113023022132101 |
5 | 210424341423401100423 |
6 | 2033401420544300305 |
7 | 62634132522450341 |
oct | 6040052713123621 |
9 | 1028240007466135 |
10 | 213311013300113 |
11 | 61a70769001763 |
12 | 1bb1112a911695 |
13 | 92041b0679211 |
14 | 3a96445720d21 |
15 | 199da97c00078 |
hex | c201572ca791 |
213311013300113 has 2 divisors, whose sum is σ = 213311013300114. Its totient is φ = 213311013300112.
The previous prime is 213311013300097. The next prime is 213311013300137. The reversal of 213311013300113 is 311003310113312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 190568720543569 + 22742292756544 = 13804663^2 + 4768888^2 .
It is a cyclic number.
It is not a de Polignac number, because 213311013300113 - 24 = 213311013300097 is a prime.
It is not a weakly prime, because it can be changed into another prime (213311013300163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106655506650056 + 106655506650057.
It is an arithmetic number, because the mean of its divisors is an integer number (106655506650057).
Almost surely, 2213311013300113 is an apocalyptic number.
It is an amenable number.
213311013300113 is a deficient number, since it is larger than the sum of its proper divisors (1).
213311013300113 is an equidigital number, since it uses as much as digits as its factorization.
213311013300113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 213311013300113 its reverse (311003310113312), we get a palindrome (524314323413425).
The spelling of 213311013300113 in words is "two hundred thirteen trillion, three hundred eleven billion, thirteen million, three hundred thousand, one hundred thirteen".
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