Base | Representation |
---|---|
bin | 10011110111011011… |
… | …110011011100000001 |
3 | 2001001121021200111001 |
4 | 103313123303130001 |
5 | 322141232130423 |
6 | 13444400052001 |
7 | 1353414420466 |
oct | 236733633401 |
9 | 61047250431 |
10 | 21331130113 |
11 | 9056959857 |
12 | 4173904001 |
13 | 201c3c20a7 |
14 | 1064dcb66d |
15 | 84ca59cad |
hex | 4f76f3701 |
21331130113 has 2 divisors, whose sum is σ = 21331130114. Its totient is φ = 21331130112.
The previous prime is 21331130111. The next prime is 21331130123. The reversal of 21331130113 is 31103113312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15282646129 + 6048483984 = 123623^2 + 77772^2 .
It is a cyclic number.
It is not a de Polignac number, because 21331130113 - 21 = 21331130111 is a prime.
It is a super-2 number, since 2×213311301132 (a number of 21 digits) contains 22 as substring.
Together with 21331130111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (21331130111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10665565056 + 10665565057.
It is an arithmetic number, because the mean of its divisors is an integer number (10665565057).
Almost surely, 221331130113 is an apocalyptic number.
It is an amenable number.
21331130113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21331130113 is an equidigital number, since it uses as much as digits as its factorization.
21331130113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 21331130113 its reverse (31103113312), we get a palindrome (52434243425).
The spelling of 21331130113 in words is "twenty-one billion, three hundred thirty-one million, one hundred thirty thousand, one hundred thirteen".
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