Base | Representation |
---|---|
bin | 110000100000000110010100… |
… | …000010001000001000011011 |
3 | 1000222021102122102210111111021 |
4 | 300200012110002020020123 |
5 | 210424401021242411103 |
6 | 2033402110140543311 |
7 | 62634200031245164 |
oct | 6040062402101033 |
9 | 1028242572714437 |
10 | 213312034341403 |
11 | 61a71142397138 |
12 | 1bb11374851b37 |
13 | 920431407276a |
14 | 3a9650118876b |
15 | 199db0768abbd |
hex | c2019408821b |
213312034341403 has 4 divisors (see below), whose sum is σ = 216234117003688. Its totient is φ = 210389951679120.
The previous prime is 213312034341317. The next prime is 213312034341457. The reversal of 213312034341403 is 304143430213312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213312034341403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213312034341493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1461041331033 + ... + 1461041331178.
It is an arithmetic number, because the mean of its divisors is an integer number (54058529250922).
Almost surely, 2213312034341403 is an apocalyptic number.
213312034341403 is a deficient number, since it is larger than the sum of its proper divisors (2922082662285).
213312034341403 is an equidigital number, since it uses as much as digits as its factorization.
213312034341403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2922082662284.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 213312034341403 its reverse (304143430213312), we get a palindrome (517455464554715).
The spelling of 213312034341403 in words is "two hundred thirteen trillion, three hundred twelve billion, thirty-four million, three hundred forty-one thousand, four hundred three".
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