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213312034341457 is a prime number
BaseRepresentation
bin110000100000000110010100…
…000010001000001001010001
31000222021102122102210111120021
4300200012110002020021101
5210424401021242411312
62033402110140543441
762634200031245302
oct6040062402101121
91028242572714507
10213312034341457
1161a71142397187
121bb11374851b81
1392043140727ac
143a965011887a9
15199db0768ac07
hexc20194088251

213312034341457 has 2 divisors, whose sum is σ = 213312034341458. Its totient is φ = 213312034341456.

The previous prime is 213312034341317. The next prime is 213312034341493. The reversal of 213312034341457 is 754143430213312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201932739772416 + 11379294569041 = 14210304^2 + 3373321^2 .

It is a cyclic number.

It is not a de Polignac number, because 213312034341457 - 223 = 213312025952849 is a prime.

It is not a weakly prime, because it can be changed into another prime (213312034341557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106656017170728 + 106656017170729.

It is an arithmetic number, because the mean of its divisors is an integer number (106656017170729).

Almost surely, 2213312034341457 is an apocalyptic number.

It is an amenable number.

213312034341457 is a deficient number, since it is larger than the sum of its proper divisors (1).

213312034341457 is an equidigital number, since it uses as much as digits as its factorization.

213312034341457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 43.

Adding to 213312034341457 its reverse (754143430213312), we get a palindrome (967455464554769).

The spelling of 213312034341457 in words is "two hundred thirteen trillion, three hundred twelve billion, thirty-four million, three hundred forty-one thousand, four hundred fifty-seven".