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2133144211241 is a prime number
BaseRepresentation
bin11111000010101001010…
…011011000111100101001
321112221000111011120120002
4133002221103120330221
5234422134404224431
64311541455312345
7310054205425031
oct37025123307451
97487014146502
102133144211241
117527303293aa
122a550181b6b5
13126201973514
147535d7808c1
153a74bdbe3cb
hex1f0a94d8f29

2133144211241 has 2 divisors, whose sum is σ = 2133144211242. Its totient is φ = 2133144211240.

The previous prime is 2133144211223. The next prime is 2133144211243. The reversal of 2133144211241 is 1421124413312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1549081433641 + 584062777600 = 1244621^2 + 764240^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2133144211241 is a prime.

Together with 2133144211243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2133144211243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066572105620 + 1066572105621.

It is an arithmetic number, because the mean of its divisors is an integer number (1066572105621).

Almost surely, 22133144211241 is an apocalyptic number.

It is an amenable number.

2133144211241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2133144211241 is an equidigital number, since it uses as much as digits as its factorization.

2133144211241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 29.

Adding to 2133144211241 its reverse (1421124413312), we get a palindrome (3554268624553).

The spelling of 2133144211241 in words is "two trillion, one hundred thirty-three billion, one hundred forty-four million, two hundred eleven thousand, two hundred forty-one".