Base | Representation |
---|---|
bin | 10011110111100011… |
… | …011110111010101011 |
3 | 2001001202001221221020 |
4 | 103313203132322223 |
5 | 322142241040321 |
6 | 13444511143523 |
7 | 1353440503542 |
oct | 236743367253 |
9 | 61052057836 |
10 | 21333143211 |
11 | 9058004276 |
12 | 4174514ba3 |
13 | 201c948483 |
14 | 1065393159 |
15 | 84cd064c6 |
hex | 4f78deeab |
21333143211 has 4 divisors (see below), whose sum is σ = 28444190952. Its totient is φ = 14222095472.
The previous prime is 21333143203. The next prime is 21333143233. The reversal of 21333143211 is 11234133312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21333143211 - 23 = 21333143203 is a prime.
It is a super-2 number, since 2×213331432112 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (21333143281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3555523866 + ... + 3555523871.
It is an arithmetic number, because the mean of its divisors is an integer number (7111047738).
Almost surely, 221333143211 is an apocalyptic number.
21333143211 is a deficient number, since it is larger than the sum of its proper divisors (7111047741).
21333143211 is an equidigital number, since it uses as much as digits as its factorization.
21333143211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7111047740.
The product of its digits is 1296, while the sum is 24.
Adding to 21333143211 its reverse (11234133312), we get a palindrome (32567276523).
The spelling of 21333143211 in words is "twenty-one billion, three hundred thirty-three million, one hundred forty-three thousand, two hundred eleven".
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