Base | Representation |
---|---|
bin | 11111000011011100100… |
… | …011110001100011001011 |
3 | 21120000020102021200222210 |
4 | 133003130203301203023 |
5 | 234430420030104311 |
6 | 4312203054520203 |
7 | 310114416636423 |
oct | 37033443614313 |
9 | 7500212250883 |
10 | 2134004144331 |
11 | 753031784904 |
12 | 2a5701806063 |
13 | 12630ab7ba77 |
14 | 75401a6b483 |
15 | 3a79c6343a6 |
hex | 1f0dc8f18cb |
2134004144331 has 8 divisors (see below), whose sum is σ = 2849038912720. Its totient is φ = 1420819402752.
The previous prime is 2134004144323. The next prime is 2134004144369. The reversal of 2134004144331 is 1334414004312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2134004144331 - 23 = 2134004144323 is a prime.
It is a super-2 number, since 2×21340041443312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2134004844331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 462504010 + ... + 462508623.
It is an arithmetic number, because the mean of its divisors is an integer number (356129864090).
Almost surely, 22134004144331 is an apocalyptic number.
2134004144331 is a deficient number, since it is larger than the sum of its proper divisors (715034768389).
2134004144331 is an equidigital number, since it uses as much as digits as its factorization.
2134004144331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 925013405.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 2134004144331 its reverse (1334414004312), we get a palindrome (3468418148643).
The spelling of 2134004144331 in words is "two trillion, one hundred thirty-four billion, four million, one hundred forty-four thousand, three hundred thirty-one".
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