Base | Representation |
---|---|
bin | 11111000011011100111… |
… | …010101011010000101001 |
3 | 21120000020211120201022111 |
4 | 133003130322223100221 |
5 | 234430423044213011 |
6 | 4312203431322321 |
7 | 310114521652453 |
oct | 37033472532051 |
9 | 7500224521274 |
10 | 2134010147881 |
11 | 753035105417 |
12 | 2a57038203a1 |
13 | 12630c1a1571 |
14 | 754027912d3 |
15 | 3a79ce1d121 |
hex | 1f0dceab429 |
2134010147881 has 2 divisors, whose sum is σ = 2134010147882. Its totient is φ = 2134010147880.
The previous prime is 2134010147851. The next prime is 2134010147933. The reversal of 2134010147881 is 1887410104312.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1506365930281 + 627644217600 = 1227341^2 + 792240^2 .
It is a cyclic number.
It is not a de Polignac number, because 2134010147881 - 215 = 2134010115113 is a prime.
It is a super-2 number, since 2×21340101478812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2134010147821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067005073940 + 1067005073941.
It is an arithmetic number, because the mean of its divisors is an integer number (1067005073941).
Almost surely, 22134010147881 is an apocalyptic number.
It is an amenable number.
2134010147881 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134010147881 is an equidigital number, since it uses as much as digits as its factorization.
2134010147881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 40.
The spelling of 2134010147881 in words is "two trillion, one hundred thirty-four billion, ten million, one hundred forty-seven thousand, eight hundred eighty-one".
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