Base | Representation |
---|---|
bin | 11111000011011110101… |
… | …100101011011101011101 |
3 | 21120000022220211001011002 |
4 | 133003132230223131131 |
5 | 234431003222024432 |
6 | 4312210420040045 |
7 | 310115333662436 |
oct | 37033654533535 |
9 | 7500286731132 |
10 | 2134040033117 |
11 | 75304aa67663 |
12 | 2a5711833025 |
13 | 126315436235 |
14 | 7540673048d |
15 | 3a7a0872e62 |
hex | 1f0deb2b75d |
2134040033117 has 2 divisors, whose sum is σ = 2134040033118. Its totient is φ = 2134040033116.
The previous prime is 2134040033071. The next prime is 2134040033123. The reversal of 2134040033117 is 7113300404312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1191614575321 + 942425457796 = 1091611^2 + 970786^2 .
It is a cyclic number.
It is not a de Polignac number, because 2134040033117 - 224 = 2134023255901 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2134040033117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2134040023117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067020016558 + 1067020016559.
It is an arithmetic number, because the mean of its divisors is an integer number (1067020016559).
Almost surely, 22134040033117 is an apocalyptic number.
It is an amenable number.
2134040033117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134040033117 is an equidigital number, since it uses as much as digits as its factorization.
2134040033117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 2134040033117 its reverse (7113300404312), we get a palindrome (9247340437429).
The spelling of 2134040033117 in words is "two trillion, one hundred thirty-four billion, forty million, thirty-three thousand, one hundred seventeen".
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