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213404940897 = 371134980299
BaseRepresentation
bin1100011010111111101…
…1001111101001100001
3202101211120001020102220
43012233323033221201
511444023131102042
6242011544301253
721263242032231
oct3065773175141
9671746036386
10213404940897
1182560586755
1235438a71829
131717c572375
14a486539cc1
1558402138ec
hex31afecfa61

213404940897 has 4 divisors (see below), whose sum is σ = 284539921200. Its totient is φ = 142269960596.

The previous prime is 213404940877. The next prime is 213404940911. The reversal of 213404940897 is 798049404312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213404940897 - 210 = 213404939873 is a prime.

It is not an unprimeable number, because it can be changed into a prime (213404940877) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35567490147 + ... + 35567490152.

It is an arithmetic number, because the mean of its divisors is an integer number (71134980300).

Almost surely, 2213404940897 is an apocalyptic number.

It is an amenable number.

213404940897 is a deficient number, since it is larger than the sum of its proper divisors (71134980303).

213404940897 is an equidigital number, since it uses as much as digits as its factorization.

213404940897 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71134980302.

The product of its (nonzero) digits is 1741824, while the sum is 51.

The spelling of 213404940897 in words is "two hundred thirteen billion, four hundred four million, nine hundred forty thousand, eight hundred ninety-seven".

Divisors: 1 3 71134980299 213404940897