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2134113251 = 12941164911
BaseRepresentation
bin111111100110011…
…1111101111100011
312111201201012000112
41333030333233203
513332313111001
6551433241535
7103612443344
oct17714775743
95451635015
102134113251
119a5718966
124b68632ab
132801a310a
1416360a0cb
15c7554cbb
hex7f33fbe3

2134113251 has 4 divisors (see below), whose sum is σ = 2134291104. Its totient is φ = 2133935400.

The previous prime is 2134113239. The next prime is 2134113257. The reversal of 2134113251 is 1523114312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2134113251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2134113257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69515 + ... + 95396.

It is an arithmetic number, because the mean of its divisors is an integer number (533572776).

Almost surely, 22134113251 is an apocalyptic number.

2134113251 is a deficient number, since it is larger than the sum of its proper divisors (177853).

2134113251 is a wasteful number, since it uses less digits than its factorization.

2134113251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177852.

The product of its digits is 720, while the sum is 23.

The square root of 2134113251 is about 46196.4636200651. The cubic root of 2134113251 is about 1287.4760358250.

Adding to 2134113251 its reverse (1523114312), we get a palindrome (3657227563).

The spelling of 2134113251 in words is "two billion, one hundred thirty-four million, one hundred thirteen thousand, two hundred fifty-one".

Divisors: 1 12941 164911 2134113251