Base | Representation |
---|---|
bin | 11111000011100011111… |
… | …011011100110110000101 |
3 | 21120000120000221122000022 |
4 | 133003203323130312011 |
5 | 234431143203311433 |
6 | 4312223233024525 |
7 | 310120450630655 |
oct | 37034373346605 |
9 | 7500500848008 |
10 | 2134127791493 |
11 | 753095557845 |
12 | 2a57370b5145 |
13 | 12632a681a79 |
14 | 75414256365 |
15 | 3a7a840a698 |
hex | 1f0e3edcd85 |
2134127791493 has 2 divisors, whose sum is σ = 2134127791494. Its totient is φ = 2134127791492.
The previous prime is 2134127791457. The next prime is 2134127791613. The reversal of 2134127791493 is 3941977214312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2134059348964 + 68442529 = 1460842^2 + 8273^2 .
It is a cyclic number.
It is not a de Polignac number, because 2134127791493 - 228 = 2133859356037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2134127791423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067063895746 + 1067063895747.
It is an arithmetic number, because the mean of its divisors is an integer number (1067063895747).
Almost surely, 22134127791493 is an apocalyptic number.
It is an amenable number.
2134127791493 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134127791493 is an equidigital number, since it uses as much as digits as its factorization.
2134127791493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2286144, while the sum is 53.
The spelling of 2134127791493 in words is "two trillion, one hundred thirty-four billion, one hundred twenty-seven million, seven hundred ninety-one thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •