Base | Representation |
---|---|
bin | 11111000011100011111… |
… | …011011100110110101101 |
3 | 21120000120000221122001210 |
4 | 133003203323130312231 |
5 | 234431143203312113 |
6 | 4312223233025033 |
7 | 310120450631043 |
oct | 37034373346655 |
9 | 7500500848053 |
10 | 2134127791533 |
11 | 753095557881 |
12 | 2a57370b5179 |
13 | 12632a681aaa |
14 | 75414256393 |
15 | 3a7a840a6c3 |
hex | 1f0e3edcdad |
2134127791533 has 16 divisors (see below), whose sum is σ = 2854029945600. Its totient is φ = 1418494936320.
The previous prime is 2134127791493. The next prime is 2134127791613. The reversal of 2134127791533 is 3351977214312.
It is not a de Polignac number, because 2134127791533 - 212 = 2134127787437 is a prime.
It is a super-3 number, since 3×21341277915333 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2134127790533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 608268 + ... + 2153658.
It is an arithmetic number, because the mean of its divisors is an integer number (178376871600).
Almost surely, 22134127791533 is an apocalyptic number.
It is an amenable number.
2134127791533 is a deficient number, since it is larger than the sum of its proper divisors (719902154067).
2134127791533 is a wasteful number, since it uses less digits than its factorization.
2134127791533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1546772.
The product of its digits is 952560, while the sum is 48.
It can be divided in two parts, 213412779 and 1533, that added together give a palindrome (213414312).
The spelling of 2134127791533 in words is "two trillion, one hundred thirty-four billion, one hundred twenty-seven million, seven hundred ninety-one thousand, five hundred thirty-three".
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