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21341333214433 = 294571610302061
BaseRepresentation
bin1001101101000111010101…
…00101011101010011100001
32210120012201012112210202201
410312203222211131103201
510244124022300330213
6113220023444013201
74331601063151531
oct466435245352341
983505635483681
1021341333214433
116888899260a81
122488115391201
13bba62c7277bb
1453acd709d4c1
1527020c8446dd
hex1368ea95d4e1

21341333214433 has 8 divisors (see below), whose sum is σ = 22125550331880. Its totient is φ = 20560336702080.

The previous prime is 21341333214413. The next prime is 21341333214437. The reversal of 21341333214433 is 33441233314312.

It can be written as a sum of positive squares in 4 ways, for example, as 9256727145169 + 12084606069264 = 3042487^2 + 3476292^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21341333214433 - 241 = 19142309958881 is a prime.

It is a super-2 number, since 2×213413332144332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21341333214392 and 21341333214401.

It is not an unprimeable number, because it can be changed into a prime (21341333214437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 805137778 + ... + 805164283.

It is an arithmetic number, because the mean of its divisors is an integer number (2765693791485).

Almost surely, 221341333214433 is an apocalyptic number.

It is an amenable number.

21341333214433 is a deficient number, since it is larger than the sum of its proper divisors (784217117447).

21341333214433 is a wasteful number, since it uses less digits than its factorization.

21341333214433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1610302547.

The product of its digits is 186624, while the sum is 37.

Adding to 21341333214433 its reverse (33441233314312), we get a palindrome (54782566528745).

The spelling of 21341333214433 in words is "twenty-one trillion, three hundred forty-one billion, three hundred thirty-three million, two hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 29 457 13253 1610302061 46698759769 735908041877 21341333214433