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213414001331 is a prime number
BaseRepresentation
bin1100011011000001110…
…1110011101010110011
3202101212012002120000112
43012300131303222303
511444032441020311
6242012510411535
721263412036416
oct3066035635263
9671765076015
10213414001331
1182565704a13
123543bb00bab
13171813c537b
14a487817b7d
155840e0328b
hex31b0773ab3

213414001331 has 2 divisors, whose sum is σ = 213414001332. Its totient is φ = 213414001330.

The previous prime is 213414001327. The next prime is 213414001349. The reversal of 213414001331 is 133100414312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213414001331 - 22 = 213414001327 is a prime.

It is a super-2 number, since 2×2134140013312 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 213414001297 and 213414001306.

It is not a weakly prime, because it can be changed into another prime (213414201331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106707000665 + 106707000666.

It is an arithmetic number, because the mean of its divisors is an integer number (106707000666).

Almost surely, 2213414001331 is an apocalyptic number.

213414001331 is a deficient number, since it is larger than the sum of its proper divisors (1).

213414001331 is an equidigital number, since it uses as much as digits as its factorization.

213414001331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 213414001331 its reverse (133100414312), we get a palindrome (346514415643).

The spelling of 213414001331 in words is "two hundred thirteen billion, four hundred fourteen million, one thousand, three hundred thirty-one".