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21342002403 = 37114000801
BaseRepresentation
bin10011111000000101…
…010001110011100011
32001002100202001110110
4103320011101303203
5322202023034103
613445425102403
71353606012231
oct237005216343
961070661413
1021342002403
119062005317
124177487a03
13202172a9b7
14106661b951
1584d9a6403
hex4f8151ce3

21342002403 has 4 divisors (see below), whose sum is σ = 28456003208. Its totient is φ = 14228001600.

The previous prime is 21342002399. The next prime is 21342002411. The reversal of 21342002403 is 30420024312.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 21342002403 - 22 = 21342002399 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21342002403.

It is not an unprimeable number, because it can be changed into a prime (21342004403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3557000398 + ... + 3557000403.

It is an arithmetic number, because the mean of its divisors is an integer number (7114000802).

Almost surely, 221342002403 is an apocalyptic number.

21342002403 is a deficient number, since it is larger than the sum of its proper divisors (7114000805).

21342002403 is an equidigital number, since it uses as much as digits as its factorization.

21342002403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7114000804.

The product of its (nonzero) digits is 1152, while the sum is 21.

Adding to 21342002403 its reverse (30420024312), we get a palindrome (51762026715).

The spelling of 21342002403 in words is "twenty-one billion, three hundred forty-two million, two thousand, four hundred three".

Divisors: 1 3 7114000801 21342002403