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2134241421311 is a prime number
BaseRepresentation
bin11111000011101010101…
…100111010011111111111
321120000211221202121211002
4133003222230322133333
5234431411300440221
64312242412320515
7310123330521146
oct37035254723777
97500757677732
102134241421311
1175314370858a
122a576917313b
1312634808834c
147542539475d
153a7b33a380b
hex1f0eab3a7ff

2134241421311 has 2 divisors, whose sum is σ = 2134241421312. Its totient is φ = 2134241421310.

The previous prime is 2134241421287. The next prime is 2134241421317. The reversal of 2134241421311 is 1131241424312.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2134241421311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2134241421317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067120710655 + 1067120710656.

It is an arithmetic number, because the mean of its divisors is an integer number (1067120710656).

Almost surely, 22134241421311 is an apocalyptic number.

2134241421311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2134241421311 is an equidigital number, since it uses as much as digits as its factorization.

2134241421311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608, while the sum is 29.

Adding to 2134241421311 its reverse (1131241424312), we get a palindrome (3265482845623).

It can be divided in two parts, 2134241 and 421311, that added together give a palindrome (2555552).

The spelling of 2134241421311 in words is "two trillion, one hundred thirty-four billion, two hundred forty-one million, four hundred twenty-one thousand, three hundred eleven".