Base | Representation |
---|---|
bin | 11111000011101010110… |
… | …010111111000111011111 |
3 | 21120000212001202111022202 |
4 | 133003222302333013133 |
5 | 234431412202404322 |
6 | 4312242510402115 |
7 | 310123350200663 |
oct | 37035262770737 |
9 | 7500761674282 |
10 | 2134243013087 |
11 | 7531445a54a9 |
12 | 2a576980033b |
13 | 1263484c4a23 |
14 | 7542568a8a3 |
15 | 3a7b35ba292 |
hex | 1f0eacbf1df |
2134243013087 has 2 divisors, whose sum is σ = 2134243013088. Its totient is φ = 2134243013086.
The previous prime is 2134243013051. The next prime is 2134243013093. The reversal of 2134243013087 is 7803103424312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2134243013087 - 214 = 2134242996703 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2134243013087.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2134243013047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067121506543 + 1067121506544.
It is an arithmetic number, because the mean of its divisors is an integer number (1067121506544).
Almost surely, 22134243013087 is an apocalyptic number.
2134243013087 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134243013087 is an equidigital number, since it uses as much as digits as its factorization.
2134243013087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 2134243013087 its reverse (7803103424312), we get a palindrome (9937346437399).
The spelling of 2134243013087 in words is "two trillion, one hundred thirty-four billion, two hundred forty-three million, thirteen thousand, eighty-seven".
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