Base | Representation |
---|---|
bin | 11001011100010… |
… | …01100100110001 |
3 | 112212121002021122 |
4 | 30232021210301 |
5 | 414114040213 |
6 | 33102232025 |
7 | 5201035445 |
oct | 1456114461 |
9 | 485532248 |
10 | 213424433 |
11 | aa521a32 |
12 | 5b585615 |
13 | 352a7761 |
14 | 204b8825 |
15 | 13b0bd08 |
hex | cb89931 |
213424433 has 4 divisors (see below), whose sum is σ = 213455088. Its totient is φ = 213393780.
The previous prime is 213424411. The next prime is 213424439. The reversal of 213424433 is 334424312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 213424433 - 214 = 213408049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213424439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710 + ... + 20672.
It is an arithmetic number, because the mean of its divisors is an integer number (53363772).
Almost surely, 2213424433 is an apocalyptic number.
It is an amenable number.
213424433 is a deficient number, since it is larger than the sum of its proper divisors (30655).
213424433 is a wasteful number, since it uses less digits than its factorization.
213424433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30654.
The product of its digits is 6912, while the sum is 26.
The square root of 213424433 is about 14609.0531178444. The cubic root of 213424433 is about 597.6056737868.
Adding to 213424433 its reverse (334424312), we get a palindrome (547848745).
The spelling of 213424433 in words is "two hundred thirteen million, four hundred twenty-four thousand, four hundred thirty-three".
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