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2134250113 = 12716805119
BaseRepresentation
bin111111100110110…
…0001001010000001
312111201222010202111
41333031201022001
513332332000423
6551440215321
7103613553352
oct17715411201
95451863674
102134250113
119a5801776
124b690a541
132802204b8
14163643d29
15c758060d
hex7f361281

2134250113 has 4 divisors (see below), whose sum is σ = 2151055360. Its totient is φ = 2117444868.

The previous prime is 2134250077. The next prime is 2134250143. The reversal of 2134250113 is 3110524312.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2134250113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2134250143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8402433 + ... + 8402686.

It is an arithmetic number, because the mean of its divisors is an integer number (537763840).

Almost surely, 22134250113 is an apocalyptic number.

It is an amenable number.

2134250113 is a deficient number, since it is larger than the sum of its proper divisors (16805247).

2134250113 is a wasteful number, since it uses less digits than its factorization.

2134250113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16805246.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 2134250113 is about 46197.9449001793. The cubic root of 2134250113 is about 1287.5035574477.

Adding to 2134250113 its reverse (3110524312), we get a palindrome (5244774425).

The spelling of 2134250113 in words is "two billion, one hundred thirty-four million, two hundred fifty thousand, one hundred thirteen".

Divisors: 1 127 16805119 2134250113