Base | Representation |
---|---|
bin | 110000100001110101100110… |
… | …110111000101011001101111 |
3 | 1000222200212002200102012022221 |
4 | 300201311212313011121233 |
5 | 210433330241100244312 |
6 | 2033533032134420211 |
7 | 62645630262643303 |
oct | 6041654667053157 |
9 | 1028625080365287 |
10 | 213431535556207 |
11 | 62007895744591 |
12 | 1bb30565501667 |
13 | 9212679b0b957 |
14 | 3a9c1da173d03 |
15 | 19a1c9d968207 |
hex | c21d66dc566f |
213431535556207 has 2 divisors, whose sum is σ = 213431535556208. Its totient is φ = 213431535556206.
The previous prime is 213431535556153. The next prime is 213431535556237. The reversal of 213431535556207 is 702655535134312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213431535556207 - 215 = 213431535523439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213431535556237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106715767778103 + 106715767778104.
It is an arithmetic number, because the mean of its divisors is an integer number (106715767778104).
Almost surely, 2213431535556207 is an apocalyptic number.
213431535556207 is a deficient number, since it is larger than the sum of its proper divisors (1).
213431535556207 is an equidigital number, since it uses as much as digits as its factorization.
213431535556207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340000, while the sum is 52.
The spelling of 213431535556207 in words is "two hundred thirteen trillion, four hundred thirty-one billion, five hundred thirty-five million, five hundred fifty-six thousand, two hundred seven".
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