Base | Representation |
---|---|
bin | 11111000011110000100… |
… | …110001001100101111101 |
3 | 21120001002211211202112202 |
4 | 133003300212021211331 |
5 | 234432112104431141 |
6 | 4312300304041245 |
7 | 310125641211413 |
oct | 37036046114575 |
9 | 7501084752482 |
10 | 2134340311421 |
11 | 75319451114a |
12 | 2a5796303225 |
13 | 1263627008c6 |
14 | 754345772b3 |
15 | 3a7bbdd949b |
hex | 1f0f098997d |
2134340311421 has 2 divisors, whose sum is σ = 2134340311422. Its totient is φ = 2134340311420.
The previous prime is 2134340311409. The next prime is 2134340311427. The reversal of 2134340311421 is 1241130434312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2122936420900 + 11403890521 = 1457030^2 + 106789^2 .
It is a cyclic number.
It is not a de Polignac number, because 2134340311421 - 210 = 2134340310397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2134340311427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067170155710 + 1067170155711.
It is an arithmetic number, because the mean of its divisors is an integer number (1067170155711).
Almost surely, 22134340311421 is an apocalyptic number.
It is an amenable number.
2134340311421 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134340311421 is an equidigital number, since it uses as much as digits as its factorization.
2134340311421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 2134340311421 its reverse (1241130434312), we get a palindrome (3375470745733).
The spelling of 2134340311421 in words is "two trillion, one hundred thirty-four billion, three hundred forty million, three hundred eleven thousand, four hundred twenty-one".
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