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21344012413 = 153113941223
BaseRepresentation
bin10011111000001100…
…111100100001111101
32001002111112011200021
4103320030330201331
5322203031344123
613445540132141
71353632053303
oct237014744175
961074464607
1021344012413
119063158489
124178097051
132021c82859
1410669c2273
1584dc51c5d
hex4f833c87d

21344012413 has 4 divisors (see below), whose sum is σ = 21357955168. Its totient is φ = 21330069660.

The previous prime is 21344012411. The next prime is 21344012419. The reversal of 21344012413 is 31421044312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21344012413 - 21 = 21344012411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21344012411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6969081 + ... + 6972142.

It is an arithmetic number, because the mean of its divisors is an integer number (5339488792).

Almost surely, 221344012413 is an apocalyptic number.

It is an amenable number.

21344012413 is a deficient number, since it is larger than the sum of its proper divisors (13942755).

21344012413 is a wasteful number, since it uses less digits than its factorization.

21344012413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13942754.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 21344012413 its reverse (31421044312), we get a palindrome (52765056725).

The spelling of 21344012413 in words is "twenty-one billion, three hundred forty-four million, twelve thousand, four hundred thirteen".

Divisors: 1 1531 13941223 21344012413