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213440131 is a prime number
BaseRepresentation
bin11001011100011…
…01011010000011
3112212121212211001
430232031122003
5414120041011
633102432431
75201132302
oct1456153203
9485555731
10213440131
11aa532803
125b592717
13352b1948
14204c0439
1513b117c1
hexcb8d683

213440131 has 2 divisors, whose sum is σ = 213440132. Its totient is φ = 213440130.

The previous prime is 213440119. The next prime is 213440147. The reversal of 213440131 is 131044312.

213440131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213440131 - 25 = 213440099 is a prime.

It is a super-2 number, since 2×2134401312 = 91113379042594322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213440099 and 213440108.

It is not a weakly prime, because it can be changed into another prime (213440231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106720065 + 106720066.

It is an arithmetic number, because the mean of its divisors is an integer number (106720066).

Almost surely, 2213440131 is an apocalyptic number.

213440131 is a deficient number, since it is larger than the sum of its proper divisors (1).

213440131 is an equidigital number, since it uses as much as digits as its factorization.

213440131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 213440131 is about 14609.5903775568. The cubic root of 213440131 is about 597.6203253175.

Adding to 213440131 its reverse (131044312), we get a palindrome (344484443).

The spelling of 213440131 in words is "two hundred thirteen million, four hundred forty thousand, one hundred thirty-one".