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213443130141119 is a prime number
BaseRepresentation
bin110000100010000000011001…
…111100111010100110111111
31000222201222000201200010201202
4300202000121330322212333
5210434023012304003434
62033542230442530115
762646520512202664
oct6042003174724677
91028658021603652
10213443130141119
11620117a557186a
121bb3286050693b
1392137a6c87198
143a9c9b9dbba6b
1519a222b805a7e
hexc22019f3a9bf

213443130141119 has 2 divisors, whose sum is σ = 213443130141120. Its totient is φ = 213443130141118.

The previous prime is 213443130141113. The next prime is 213443130141167. The reversal of 213443130141119 is 911141031344312.

213443130141119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213443130141119 - 216 = 213443130075583 is a prime.

It is a super-2 number, since 2×2134431301411192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213443130141113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106721565070559 + 106721565070560.

It is an arithmetic number, because the mean of its divisors is an integer number (106721565070560).

Almost surely, 2213443130141119 is an apocalyptic number.

213443130141119 is a deficient number, since it is larger than the sum of its proper divisors (1).

213443130141119 is an equidigital number, since it uses as much as digits as its factorization.

213443130141119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 213443130141119 in words is "two hundred thirteen trillion, four hundred forty-three billion, one hundred thirty million, one hundred forty-one thousand, one hundred nineteen".