2135040001331 has 4 divisors (see below), whose sum is σ = 2135127631464. Its totient is φ = 2134952371200.

The previous prime is 2135040001309. The next prime is 2135040001361. The reversal of 2135040001331 is 1331000405312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2135040001331 - 2¹⁴ = 2135039984947 is a prime.

It is a super-2 number, since 2×2135040001331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2135040001297 and 2135040001306.

It is not an unprimeable number, because it can be changed into a prime (2135040001301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43778510 + ... + 43827251.

It is an arithmetic number, because the mean of its divisors is an integer number (533781907866).

Almost surely, 2^{2135040001331} is an apocalyptic number.

2135040001331 is a deficient number, since it is larger than the sum of its proper divisors (87630133).

2135040001331 is an equidigital number, since it uses as much as digits as its factorization.

2135040001331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87630132.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 2135040001331 its reverse (1331000405312), we get a palindrome (3466040406643).

The spelling of 2135040001331 in words is "two trillion, one hundred thirty-five billion, forty million, one thousand, three hundred thirty-one".