Base | Representation |
---|---|
bin | 1001101101011110111110… |
… | …00110010111001010110111 |
3 | 2210121102110202011102021012 |
4 | 10312233133012113022313 |
5 | 10244331021001242401 |
6 | 113225523121542435 |
7 | 4332530441114666 |
oct | 466573706271267 |
9 | 83542422142235 |
10 | 21354025415351 |
11 | 6893211715422 |
12 | 248a677aa4a1b |
13 | bbb8a30ca865 |
14 | 53b77c9c4ddd |
15 | 270701c468bb |
hex | 136bdf1972b7 |
21354025415351 has 4 divisors (see below), whose sum is σ = 21354038164032. Its totient is φ = 21354012666672.
The previous prime is 21354025415323. The next prime is 21354025415383. The reversal of 21354025415351 is 15351452045312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21354025415351 - 210 = 21354025414327 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21354025415299 and 21354025415308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21354025415251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3398870 + ... + 7366163.
It is an arithmetic number, because the mean of its divisors is an integer number (5338509541008).
Almost surely, 221354025415351 is an apocalyptic number.
21354025415351 is a deficient number, since it is larger than the sum of its proper divisors (12748681).
21354025415351 is a wasteful number, since it uses less digits than its factorization.
21354025415351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12748680.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 21354025415351 in words is "twenty-one trillion, three hundred fifty-four billion, twenty-five million, four hundred fifteen thousand, three hundred fifty-one".
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